.net Json和Xml解析

浏览数：24 / 时间：2015年06月09日

引言

Json和Xml是现在跨平台传输数据的主流格式,关于它们的解析,网上资料很多,我稍作整理,写成一个小demo,方便日后使用.

JSON解析

能进行json解析的类库有很多,例如JavaScriptSerializer,DataContractJsonSerializer和开源类库Newtonsoft.Json.这里使用Newtonsoft.Json作个演示.

1.定义示例的类

   public class Data
    {
        public string Name { get; set; }
        public int Jobnum { get; set; }
        public DateTime Date { get; set; }
    }

2.调用静态类JsonConvert进行序列化和反序列化,很简单,代码如下

          List<Data> datas = new List<Data>();
          datas.Add(new Data { Jobnum = 1, Name = "张三" ,Date=DateTime.Now});
          datas.Add(new Data { Jobnum = 2, Name = "李四", Date = DateTime.Now });
          string reslut=  JsonConvert.SerializeObject(datas);
          List<Data>  dataresult =  JsonConvert.DeserializeObject<List<Data>>(reslut);

XML解析

1.xml解析需要用到XmlSerializer类,对象类要加上[Serializable],如下

   [Serializable]
    public class Data
    {
        public string Name { get; set; }
        public int Jobnum { get; set; }
        public DateTime Date { get; set; }
    }

2.编写XMLSerialize静态解析类,代码如下

public static class XMLSerialize
    {

        public static string Serialize<T>(object obj)
        {
            XmlSerializer xml = new XmlSerializer(typeof(T));

            using (StringWriter reader = new StringWriter())
            {
                xml.Serialize(reader, obj);
                return reader.ToString();
            }
        }

        public static T DeSerialize<T>(string xmlstr)
        {
            XmlSerializer xml = new XmlSerializer(typeof(T));
            using (StringReader reader = new StringReader(xmlstr))  
            {
                return (T)xml.Deserialize(reader);  
            }  
        }
    }

3.调用静态类XMLSerialize方法进行序列和反序列化

            List<Data> datas = new List<Data>();
            datas.Add(new Data { Jobnum = 1, Name = "张三", Date = DateTime.Now });
            datas.Add(new Data { Jobnum = 2, Name = "李四", Date = DateTime.Now });

            string xmlstr = XMLSerialize.Serialize<List<Data>>(datas);
     
            List<Data> obj = XMLSerialize.DeSerialize<List<Data>>(xmlstr);