angularjs学习笔记之一（ajax请求）

浏览数：19 / 时间：2015年06月09日

实现ajax请求

【HTML 代码】

<!DOCTYPE html>
<html>
<head>
    <meta charset="utf-8">
    <meta name="viewport" content="width=device-width,user-scalable=no, initial-scale=1">
    <link rel="stylesheet" type="text/css" href="" />
    <title>angularjs实现 ajax</title>
</head>
<body ng-app="HelloAjax">
   <div ng-controller="HelloAjax">
       <form>
	       <input type="text" ng-model="username" />
		   <input type="text" ng-model="email" />
	   </form>
	   <table> 
	      <tr ng-repeat="user in users">
			 <td>{{user.username}}</td>
		     <td>{{user.email}}</td>
		  </tr>
	   </table>
	   <button ng-click="get_more();">get more</button>
   </div>
</body>
<script type="text/javascript" src="./js/angular.min.js" charset="utf-8"></script>
	<script type="text/javascript" src="ajax.js" charset="utf-8"></script>
</html>

【js代码 ajax.js】

var myModule = angular.module("HelloAjax",[]);
myModule.controller("HelloAjax",["$scope","$http",function HelloAjax($scope,$http){
    
	/*
	$scope.users=[{'username':"zhangsan","email":"[email protected]"},
		{'username':"zhangsan2","email":"[email protected]"},
		{'username':"zhangsan3","email":"[email protected]"}];
	*/
	$scope.get_more = function(){

		$http({
				method: "POST", 
				url: "./ajax.php",
				data:{'username':$scope.username,
					  'email':$scope.email
					}
			}).
			success(function(data, status) {
			  //$scope.status = status;
			   $scope.users = data;
			}).
			error(function(data, status) {
			  //$scope.data = data || "Request failed";
			  //$scope.status = status;
		  });
	  }


	

}]);

【PHP代码 ajax.php】

<?php

//获取参数
$data = file_get_contents("php://input");
$user = json_decode($data);

//查询数据库
$conn = mysql_connect("localhost","root","");
mysql_select_db("test");
$sql ="select username,email from users ";
$res = mysql_query($sql,$conn);
$users = array();
while($row = mysql_fetch_assoc($res)){
   $users[] = $row;
}

//当然这里简化了插入数据库
$users[] = array('username'=>$user->username,
                 'email'=>$user->email);

//返回数据库
echo json_encode($users);

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angularjs学习笔记之一（ajax请求）