Hibernate中单向一对多删除级联数据问题

	public static void main(String[] args) {

		// test();
		// test1();
		// test2();
		// test3();
		// test4();

		// test5();

		// 测试one2many 单向
		test6();
		// 测试单向 维护关系 delete删除操作
		// test7();
		// 测试单向 维护关系 delete更新操作
		// test8();

	}

	private static void test8() {
		// 获得 session 开启事务
		SessionFactory sessionFactory = new Configuration().configure()
				.buildSessionFactory();
		Session session = sessionFactory.openSession();
		session.beginTransaction();

		// 新建 一方数据 设置ID 为主键值
		PersonInfo personinfo = new PersonInfo();
		personinfo.setPerId("4028e5734cf9ddc8014cf9ddc9860001");
		// 删除该对象 并未执行删除多方数据
		session.delete(personinfo);
		session.flush();
		// 提交事务
		session.getTransaction().commit();
		// 关闭session
		session.close();

	}

	private static void test7() {
		// 获得 session 开启事务
		SessionFactory sessionFactory = new Configuration().configure()
				.buildSessionFactory();
		Session session = sessionFactory.openSession();
		session.beginTransaction();
		// 载入该对象
		PersonInfo personinfo = (PersonInfo) session.load(PersonInfo.class,
				"4028e5734cf9d163014cf9d164fc0001");
		// 取出多方数据集合
		Set<One2Many> set = personinfo.getOne2many();
		Iterator<One2Many> iterator = set.iterator();
		// 迭代输出 多方 主键值
		while (iterator.hasNext()) {
			System.out.println(iterator.next().getTest4());
		}
		// 删除一方数据
		session.delete(personinfo);
		// 提交事务
		session.getTransaction().commit();
		// 关闭session
		session.close();
	}

	private static void test6() {

		// 获得 session 开启事务
		SessionFactory sessionFactory = new Configuration().configure()
				.buildSessionFactory();
		Session session = sessionFactory.openSession();
		session.beginTransaction();

		// 创建一方 对象值
		PersonInfo personinfo = new PersonInfo();
		personinfo.setPerName("单向one2many");

		// 创建多方数据并存入集合
		One2Many o = new One2Many();
		o.setTest2("单向1");
		One2Many o2 = new One2Many();
		o2.setTest2("单向2");
		One2Many o3 = new One2Many();
		o3.setTest2("单向3");
		HashSet<One2Many> set = new HashSet<One2Many>();
		set.add(o);
		set.add(o2);
		set.add(o3);
		// 将数据绑定一方数据
		personinfo.setOne2many(set);
		// 保存一方数据
		session.save(personinfo);
		// 提交事务
		session.getTransaction().commit();
		// 关闭session
		session.close();

	}

方法7与方法8的 执行结果是不一样的。

方法8 运行结果：

Hibernate: update Test set b=null where b=?

Hibernate: update one2many set test3=null where test3=?

Hibernate: delete from personinfo where perId=?

执行的是更新外键值为null

方法7执行结果：

Hibernate: select personinfo0_.perId as perId0_2_, personinfo0_.perName as perName0_2_, personinfo0_.perSex as perSex0_2_, personinfo0_.perAge as perAge0_2_, personinfo0_.perPhone as perPhone0_2_, personinfo0_.PerAddress as PerAddress0_2_, personinfo0_.perJob as perJob0_2_, personinfo0_.perEntryTime as perEntry8_0_2_, personinfo0_.PerDeparturetime as PerDepar9_0_2_, personinfo0_.perCreateDate as perCrea10_0_2_, personinfo0_.perLastModifyDate as perLast11_0_2_, mtwo2many1_.e as e4_, mtwo2many1_.a as a4_, mtwo2many1_.a as a4_0_, mtwo2many1_.b as b4_0_, mtwo2many1_.c as c4_0_, mtwo2many1_.d as d4_0_, mtwo2many1_.e as e4_0_, one2many2_.test3 as test4_5_, one2many2_.test4 as test1_5_, one2many2_.test4 as test1_6_1_, one2many2_.test1 as test2_6_1_, one2many2_.test2 as test3_6_1_, one2many2_.test3 as test4_6_1_ from personinfo personinfo0_ left outer join Test2 mtwo2many1_ on personinfo0_.perId=mtwo2many1_.e left outer join one2many one2many2_ on personinfo0_.perId=one2many2_.test3 where personinfo0_.perId=?

Hibernate: select one2one0_.test4 as test1_1_0_, one2one0_.test1 as test2_1_0_, one2one0_.test2 as test3_1_0_, one2one0_.test3 as test4_1_0_ from one2one one2one0_ where one2one0_.test4=?

4028e5734cf9e355014cf9e356720003

4028e5734cf9e355014cf9e356720004

4028e5734cf9e355014cf9e356720002

Hibernate: select mone2many0_.b as b1_, mone2many0_.a as a1_, mone2many0_.a as a3_0_, mone2many0_.b as b3_0_, mone2many0_.c as c3_0_ from Test mone2many0_ where mone2many0_.b=?

Hibernate: update one2many set test3=null where test3=?

Hibernate: delete from one2many where test4=?

Hibernate: delete from one2many where test4=?

Hibernate: delete from one2many where test4=?

Hibernate: delete from personinfo where perId=?

执行delete 是删除操作