[LeetCode] Happy Number
Write an algorithm to determine if a number is “happy”.
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example: 19 is a happy number
12 + 92 = 82
82 + 22 = 68
62 + 82 = 100
12 + 02 + 02 = 1
解题思路
判断中间结果是否出现重复即可
实现代码[C++]
//Rumtime:10ms
class Solution {
public:
bool isHappy(int n) {
set<int> nums;
while(true)
{
if (n == 1)
{
return true;
}
if (nums.find(n) == nums.end())
{
nums.insert(n);
int sum = 0;
while(n)
{
int x = n % 10;
sum += x * x;
n /= 10;
}
n = sum;
}
else
{
return false;
}
}
}
};
实现代码[Python]
# Runtime:76ms
class Solution:
# @param {integer} n
# @return {boolean}
def isHappy(self, n):
SQUARE = dict([(c, int(c)**2) for c in "0123456789"])
s = set()
while n != 1 and n not in s:
s.add(n)
n = sum(SQUARE[d] for d in str(n))
return n == 1
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