LeetCode:Trapping Rain Water
Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining.
For example,
Given [0,1,0,2,1,0,1,3,2,1,2,1]
, return 6
.
The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of rain water (blue section) are being trapped.Thanks Marcos for contributing this image!
// https://oj.leetcode.com/problems/trapping-rain-water/ // Author : Chao Zeng // Date : 2015-2-11 class Solution { public: int trap(int A[], int n) { int ans = 0; int maxnum = A[0]; int flag = 0; for (int i = 0; i < n; i++){ if (maxnum < A[i]){ maxnum = A[i]; flag = i; } } int currentmaxnum = A[0]; for (int i = 0; i < flag ; i++){ if (currentmaxnum < A[i]){ currentmaxnum = A[i]; } if (A[i] < maxnum && A[i] < currentmaxnum){ ans += currentmaxnum - A[i]; } } currentmaxnum = A[n - 1]; for (int i = n -1; i > flag; i--){ if (currentmaxnum < A[i]){ currentmaxnum = A[i]; } if (A[i] < maxnum && A[i] < currentmaxnum){ ans += currentmaxnum - A[i]; } } return ans; } };
郑重声明:本站内容如果来自互联网及其他传播媒体,其版权均属原媒体及文章作者所有。转载目的在于传递更多信息及用于网络分享,并不代表本站赞同其观点和对其真实性负责,也不构成任何其他建议。