Android处理大图片

项目中经常碰到需要处理大图片的问题,因为android对应用分配资源的限制,如果不进行相应的处理,容易造成OOM。

Android处理大图的方法:

对于大图先获取出图片的width和height, 然后根据view的width和height, 换算出图片inSampleSize,,最后压缩生成相应的图片。

其中重要的两个参数是:

/**
111         * If set to true, the decoder will return null (no bitmap), but
112         * the out... fields will still be set, allowing the caller to query
113         * the bitmap without having to allocate the memory for its pixels.
114         */
115        public boolean inJustDecodeBounds;
116
117        /**
118         * If set to a value > 1, requests the decoder to subsample the original
119         * image, returning a smaller image to save memory. The sample size is
120         * the number of pixels in either dimension that correspond to a single
121         * pixel in the decoded bitmap. For example, inSampleSize == 4 returns
122         * an image that is 1/4 the width/height of the original, and 1/16 the
123         * number of pixels. Any value <= 1 is treated the same as 1. Note: the
124         * decoder uses a final value based on powers of 2, any other value will
125         * be rounded down to the nearest power of 2.
126         */
127        public int inSampleSize;

InJustDecodeBounds能在不分配资源给图片的情况下获取图片的大小


inSampleSize计算图片的压缩比


开源项目xutils, Universal-Image-Loader和Foursquare对于大图的处理都类似的


下面是Foursquare处理大图的代码:

public class ImageUtils {
    
    private ImageUtils() {
    }

    public static void resampleImageAndSaveToNewLocation(String pathInput, String pathOutput) 
        throws Exception 
    {
        Bitmap bmp = resampleImage(pathInput, 640);
        
        OutputStream out = new FileOutputStream(pathOutput);
        bmp.compress(Bitmap.CompressFormat.JPEG, 90, out); 
    }
    
    public static Bitmap resampleImage(String path, int maxDim) 
        throws Exception {
        
        BitmapFactory.Options bfo = new BitmapFactory.Options(); 
        bfo.inJustDecodeBounds = true; 
        BitmapFactory.decodeFile(path, bfo); 
    
        BitmapFactory.Options optsDownSample = new BitmapFactory.Options();
        optsDownSample.inSampleSize = getClosestResampleSize(bfo.outWidth, bfo.outHeight, maxDim);
    
        Bitmap bmpt = BitmapFactory.decodeFile(path, optsDownSample);
    
        Matrix m = new Matrix(); 
        
        if (bmpt.getWidth() > maxDim || bmpt.getHeight() > maxDim) {
            BitmapFactory.Options optsScale = getResampling(bmpt.getWidth(), bmpt.getHeight(), maxDim);
            m.postScale((float)optsScale.outWidth  / (float)bmpt.getWidth(), 
                        (float)optsScale.outHeight / (float)bmpt.getHeight()); 
        }
         
        int sdk = new Integer(Build.VERSION.SDK).intValue(); 
        if (sdk > 4) {
            int rotation = ExifUtils.getExifRotation(path);
            if (rotation != 0) { 
                m.postRotate(rotation); 
            }
        }
        
        return Bitmap.createBitmap(bmpt, 0, 0, bmpt.getWidth(), bmpt.getHeight(), m, true); 
    }
    
    private static BitmapFactory.Options getResampling(int cx, int cy, int max) {
        float scaleVal = 1.0f;
        BitmapFactory.Options bfo = new BitmapFactory.Options();
        if (cx > cy) {
            scaleVal = (float)max / (float)cx;
        }
        else if (cy > cx) {
            scaleVal = (float)max / (float)cy;
        }
        else {
            scaleVal = (float)max / (float)cx;
        }
        bfo.outWidth  = (int)(cx * scaleVal + 0.5f);
        bfo.outHeight = (int)(cy * scaleVal + 0.5f);
        return bfo;
    }
    
    private static int getClosestResampleSize(int cx, int cy, int maxDim) {
        int max = Math.max(cx, cy);
        
        int resample = 1;
        for (resample = 1; resample < Integer.MAX_VALUE; resample++) {
            if (resample * maxDim > max) {
                resample--;
                break;
            }
        }
        
        if (resample > 0) {
            return resample;
        }
        return 1;
    }
    
    public static BitmapFactory.Options getBitmapDims(String path) throws Exception {
        BitmapFactory.Options bfo = new BitmapFactory.Options(); 
        bfo.inJustDecodeBounds = true; 
        BitmapFactory.decodeFile(path, bfo); 
        return bfo;
    }
}

还有一个问题需要纠正:
看了几篇关于处理大图的文章都说不要调用BitmapFactory.decodeResource这个函数,因为这个函数在完成decode后,最终都是通过java层的createBitmap来完成的,需要消耗更多内存。
我看了BitmapFactory的源码发现上面那个分析是错误的,decodeResource最终也是调用Jni去获取图片。请看下面时序图。




Android处理大图片,,5-wow.com

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