IOS -- 利用URL Scheme启动第三方应用
浏览数：154 /
时间：2015年06月11日
以启动Instagram为例
Custom URL Scheme
Opening instagram://, followed by one of the following parameters, will open our app and perform a custom action. For example, for camera, you would direct users on the iPhone to the custom URL instagram://camera.
| URL | OPENS |
|---|---|
| app | The Instagram app |
| camera | The camera (or photo library on non-camera devices) |
| media?id=MEDIA_ID | Media with this ID |
| user?username=USERNAME | User with this username |
| location?id=LOCATION_ID | Location feed for this location ID |
| tag?name=TAG | Tag feed for this tag |
The Objective-C call to open one of these URLs is as follows:
NSURL *instagramURL = [NSURL URLWithString:@"instagram://location?id=1"];
if ([[UIApplication sharedApplication] canOpenURL:instagramURL]) {
[[UIApplication sharedApplication] openURL:instagramURL];
}
//开启浏览器打开某网页 [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"https://instagram.com/"]];</span>
https://instagram.com/developer/mobile-sharing/iphone-hooks/#
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