Oracle “CONNECT BY” 用法
Oracle “CONNECT BY”是层次查询子句,一般用于树状或者层次结果集的查询。其语法是:
[ START
WITH
condition ]
CONNECT
BY
[ NOCYCLE ] condition
说明:
1. START WITH:告诉系统以哪个节点作为根结点开始查找并构造结果集,该节点即为返回记录中的最高节点。
2. 当分层查询中存在上下层互为父子节点的情况时,会返回ORA-01436错误。此时,需要在connect by后面加上NOCYCLE关键字。同时,可用connect_by_iscycle伪列定位出存在互为父子循环的具体节点。 connect_by_iscycle必须要跟关键字NOCYCLE结合起来使用
[例1]
创建一个部门表,这个表有三个字段,分别对应部门ID,部门名称,以及上级部门ID
DEPID DEPNAME UPPERDEPID
----------- -------------------------------------------------------------------------------- -----------
0 General Deparment
1 Development 0
2 QA 0
3 Server Development 1
4 Client Development 1
5 TA 2
6 Porject QA 2
现在我要根据“CONNECT BY”来实现树状查询结果
SQL>
SELECT
RPAD(
‘ ‘
, 2*(
LEVEL
-1),
‘-‘
) || DEPNAME
"DEPNAME"
,
CONNECT_BY_ROOT DEPNAME
"ROOT"
,
CONNECT_BY_ISLEAF
"ISLEAF"
,
LEVEL
,
SYS_CONNECT_BY_PATH(DEPNAME,
‘/‘
)
"PATH"
FROM
DEP
START
WITH
UPPERDEPID
IS
NULL
CONNECT
BY
PRIOR
DEPID = UPPERDEPID;
DEPNAME ROOT ISLEAF
LEVEL
PATH
------------------------------ ------------------- ---------- ---------- --------------------------------------------------------------------------------
General Deparment General Deparment 0 1 /General Deparment
-Development General Deparment 0 2 /General Deparment/Development
---Server Development General Deparment 1 3 /General Deparment/Development/Server Development
---Client Development General Deparment 1 3 /General Deparment/Development/Client Development
-QA General Deparment 0 2 /General Deparment/QA
---TA General Deparment 1 3 /General Deparment/QA/TA
---Porject QA General Deparment 1 3 /General Deparment/QA/Porject QA
说明:
1. CONNECT_BY_ROOT 返回当前节点的最顶端节点
2. CONNECT_BY_ISLEAF 判断是否为叶子节点,如果这个节点下面有子节点,则不为叶子节点
3. LEVEL 伪列表示节点深度
4. SYS_CONNECT_BY_PATH函数显示详细路径,并用“/”分隔
总结:
1.根据树形结构查子类
select
*
from
xxxx
where
levelpermission = 0
and
validflag = 1
start
with
id =
‘20130718091552GRP60000001‘
connect
by
prior
id=PARENTID
2. 根据属性结构查询父类
select
*
from
xxxx
where
levelpermission = 0
and
validflag = 1
start
with
id =
‘40288181455dbe1701455ee92b9d001d‘
connect
by
prior
PARENTID=id
2. 根据属性结构查询父类
部分转载:http://www.cnblogs.com/lettoo/archive/2010/08/03/1791239.html
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