VMware coding Challenge：Date of Weekday

浏览数：15 / 时间：2015年06月20日

技术分享

这道题再次证明了这种细节的题目，画个图容易搞清楚技术分享

 1 import java.util.Scanner;
 2 
 3 
 4 public class Solution2 {
 5     static int DateOfWeekday(int date, int weekday) {
 6         int cur = date%7;
 7         int res = 0;
 8         int dif = 0;
 9         if (weekday > 0) {
10             dif = 7*((weekday-1)/7) + (weekday%7-cur>0? weekday%7-cur : 7-(cur-weekday%7));
11             res = date + dif;
12         }
13         else if (weekday < 0){
14             weekday = Math.abs(weekday);
15             dif = 7*((weekday-1)/7) + (cur-weekday%7>0? cur-weekday%7 : 7-(weekday%7-cur));
16             res = date - dif;
17         }
18         else res = date;
19         return res;
20     }
21     
22     public static void main(String[] args) {
23         Scanner in = new Scanner(System.in);
24         int res;
25         int _date;
26         _date = Integer.parseInt(in.nextLine());
27         
28         int _weekday;
29         _weekday = Integer.parseInt(in.nextLine());
30         
31         res = DateOfWeekday(_date, _weekday);
32         System.out.println(res);
33     }
34 
35 }

 1     static int DateOfWeekday(int date, int weekday) {
 2         int cur = date % 7;
 3         int res;
 4         if (weekday == 0) return date;
 5         else if (weekday > 0) { 
 6             if (weekday % 7 > cur) res = date + weekday % 7 - cur;
 7             else res = date + 7 - (cur - weekday % 7);
 8             res = res + 7*((weekday-1)/7);
 9         }
10         else {
11             if (Math.abs(weekday % 7)<cur) res= date - cur - weekday % 7;
12             else res = date - 7 - cur - weekday%7;
13             res = res - 7*((Math.abs(weekday)-1)/7);
14         }
15         return res;
16     }