<<Python基础教程>>学习笔记 | 第06章 | 抽象

第06章  抽象

------

懒惰即美德

假如要计算斐波那契数列(任何一个数是前两数之和的数字序列)

>>> fibs=[0,1]
>>> for i in range(8):
	fibs.append(fibs[-2]+fibs[-1]) #fibs[-2]+fibs[-1]后两位数,append往后添加

#运行后，包含10个斐波那契数列的10个数字是	
>>> fibs
[0, 1, 1, 2, 3, 5, 8, 13, 21, 34]

>>> fibs = [0,1]
>>> num = input('Enter number here:')
Enter number here:10
>>> for i in range(num-2):
	fibs.append(fibs[-2]+fibs[-1])	
>>> fibs
[0, 1, 1, 2, 3, 5, 8, 13, 21, 34]

num = input('How many numbers do you want? ') 
print fibs(num)

程序应该是非常抽象的，就像"下载页面、计算频率，打印单词频率"一样易懂.
事实上我们现在就能把这段描述翻译成Python

page  = download_page()
freqs = compute_frequencies(page)
for word,freq in freqs:
    print word, freq

------

创建函数

函数可以调用，它执行某种行为并返回值。

一般来说，内建的callable函数可以判断函数是否可调用:

>>> import math
>>> x = 1
>>> y = math.sqrt
>>> callable(x)
False
>>> callable(y)
True

创建函数是组织程序的关键，那么如何定义函数呢? 下面就是个最简单的函数

>>> def hello(name):
	return 'Hello,' + name + '!'
>>> hello('Jerry')
'Hello,Jerry!'

像上面的斐波那契要写成函数的话，就方便多了，可以传入任意数字

>>> def fibs(num):
	result = [0,1]
	for i in range(num-2):
		result.append(result[-2]+result[-1])
	return result

>>> fibs(10)
[0, 1, 1, 2, 3, 5, 8, 13, 21, 34]

Note:

1. return 语句非常重要，是用来从函数中返回值的，如果没有的话，返回None

>>> def sum(x,y):
	result = x + y
>>> print sum(1,2)
None

2. return 相当于程序中的break.比如说下面的:

def test():
  print 'This is 1 line.'
  return
  print 'This is 2 line'
test()
#输出结果
>>>This is 1 line.

记录函数

如果想要函数被别人理解的话，可以用#注释，另外一个直接加上字符串

如果直接放def函数后面的话，会作为函数的一部分，称为文档字符串

>>> def square(x):
	'Calculates the square of the number x'
	return x*x

>>> square.__doc__
'Calculates the square of the number x'

>>> dir(square)
['__annotations__', '__call__', '__class__', '__closure__', '__code__', '__defaults__', '__delattr__', '__dict__', '__dir__', '__doc__', '__eq__', '__format__', '__ge__', '__get__', '__getattribute__', '__globals__', '__gt__', '__hash__', '__init__', '__kwdefaults__', '__le__', '__lt__', '__module__', '__name__', '__ne__', '__new__', '__qualname__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__']

>>> help(square)
Help on function square in module __main__:

square(x)
    Calculates the square of the number x

------

参数魔法

形参:def 后面的变量就是形式参数，简称形参

实参:调用函数提供的值就是实际参数，简称实参，或叫参数，或叫值. 

变量定义在函数体内，为局部变量，定义在函数体内，为全局变量

>>> def try_to_change(n):
	n = 'Mr, Gumby'
>>> name = 'Mrs, Smith'
>>> try_to_change(name) #将name作为实参传给try_to_change函数
>>> name                #全局变量值不变
'Mrs, Smith'

>>> def change(n):
	n[0] = 'Mr. Gumby'
>>> name = ['Mrs. Smith','Mr. Jing']
>>> change(name)
>>> name                #值已经发生了变化
['Mr. Gumby', 'Mr. Jing']

这是跟上面的区别所在，这里面的列表发生了改变:

>>> name = ['Mrs. Smith','Mr. Jing']
>>> n    = name         #模拟传参数
>>> n[0] = 'Mr. Gumby'  #改变列表
>>> name
['Mr. Gumby', 'Mr. Jing']

>>> storage={}
>>> storage['first']={}
>>> storage['middle']={}
>>> storage['last']={}
>>> storage
{'middle': {}, 'last': {}, 'first': {}}

>>> storage['first']['Magus']=[me]
>>> storage['middle']['Lei']=[me]
>>> storage['last']['Hetland']=[me]
>>> storage
{
'middle':   {'Lei': ['Magnus Lei Hetland']}, 
'last': {'Hetland': ['Magnus Lei Hetland']}, 
'first': {'Magus':  ['Magnus Lei Hetland']}
}

>>> my_sister='Anne Lei Hetland'
>>> storage['first'].setdefault('Anne',[]).append(my_sister)
>>> storage['middle'].setdefault('Lei',[]).append(my_sister)
>>> storage['last'].setdefault('Hetland',[]).append(my_sister)
>>> storage['first']['Anne']
['Anne Lei Hetland']
>>> storage['middle']['Lei']
['Magnus Lei Hetland', 'Anne Lei Hetland']

>>> def init(data):
...     data['first']={}
...     data['middle'] = {}
...     data['last'] = {}
...
>>> init(storage)
>>> storage
{'middle': {}, 'last': {}, 'first': {}}

>>> def inc(x): return x+1
...
>>> i = 10
>>> i = inc(i)
>>> i
11

>>> def inc(x):
...     x[0] = x[0] + 1
...
>>> foo = [10]
>>> inc(foo)
>>> foo
[11]

>>> def hello_1(greeting,name): 
        print "%s,%s!"%(greeting,name)
...
>>> def hello_2(name,greeting): 
        print "%s,%s!"%(name,greeting)
...

>>> hello_1('hello','world')
hello,world!
>>> hello_2('hello','world')
hello,world!

>>> hello_1(greeting='Hi', name='Jerry')
Hi,Jerry!

>>> hello_2(name='Jerry',greeting='Hi')
Jerry,Hi!

store('Mr. Smith',10,20,13,5)
store(patient='Mr. Smith',hour=10,minutes=20,day=13,month=5)

>>> def hello_3(greeting='Hello',name='World'):
...     print '%s,%s!' % (greeting,name)
...
>>> hello_3()           #如果不加参数的话，就用默认值
Hello,World!
>>> hello_3('greeting') #带参数的话，按参数顺序赋值
greeting,World!
>>> hello_3('greeting','universe') #按提供的顺序
greeting,universe!
# 如果只想提供name，而让greeting默认
>>> hello_3(name='Sherry')
Hello,Sherry!

>>> def hello_4(name,greeting='Hello',punctuation='!'):
...     print '%s, %s%s' % (greeting,name,punctuation)
...
>>> hello_4('Jerry')
Hello, Jerry!
>>> hello_4('Jerry','Howdy')
Howdy, Jerry!
>>> hello_4('Jerry','Howdy','...')
Howdy, Jerry...
>>> hello_4('Jerry',punctuation='.')
Hello, Jerry.
>>> hello_4('Jerry',greeting='Top of the morning to ya')
Top of the morning to ya, Jerry!
>>> hello_4()
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
TypeError: hello_4() takes at least 1 argument (0 given)

#如果最后一个name也用默认值的话，就不会产生上面的异常.

------

收集参数

有的时候提供多参数是很有必要的，那么如何做呢？ 很简单

>>> def print_parms(*parms):
...     print parms
...

>>> print_parms('Hello')
('Hello',)
>>> print_parms(1,2,3)
(1, 2, 3)

>>> def print_parms_2(title,*parms):
...     print title
...     print parms
...
>>> print_parms_2('Parms:',1,2,3)
Parms:
(1, 2, 3)

>>> print_parms_2('Nothing:')
Nothing:
()

>>> print_parms_2('hmm...',someting=42)
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
TypeError: print_parms_2() got an unexpected keyword argument 'someting'

>>> def print_parms_3(**parms):
...     print parms
...
>>> print_parms_3(x=1,y=2,z=3)
{'y': 2, 'x': 1, 'z': 3}

>>> def print_parms_4(x,y,z=3,*pospar,**keypar):
...     print x,y,z
...     print pospar
...     print keypar
...
>>> print_parms_4(1,2,3,5,6,7,foo=1,bar=2)
1 2 3
(5, 6, 7)
{'foo': 1, 'bar': 2}

------

反转过程

那么要如何使用*,**呢? 看下面一个简单的例子:

>>> def add(x,y): return x+y
...
>>> parms=(1,2)
#下面这样会报错
>>> add(parms)
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
TypeError: add() takes exactly 2 arguments (1 given)
#必需这样，前面加个*号
>>> add(*parms)
3

>>> def hello_3(greeting='Hello',name='World'):
...     print '%s,%s!' % (greeting,name)
...
>>> params = {'name':'Sir Robin','greeting':'Well met'}
>>> hello_3(**params)
Well met,Sir Robin!

>>> def with_star(**kwd):
...     print kwd['name'],'is',kwd['age'],'years old!'
...
>>> def without_star(kwd):
...     print kwd['name'],'is',kwd['age'],'years old!'
...
>>> args = {'name':'Mr. Gumby','age':35}
>>> with_star(**args)
Mr. Gumby is 35 years old!
>>> without_star(args)
Mr. Gumby is 35 years old!

和调用(分割字典或序列)才有用.

Note:

使用拼接(Splicing)操作符传递参数很有用，因为不用担心参数的个数

>>> def foo(x,y,z,m=0,n=0):
...     print x,y,z,m,n
...
>>> def call_foo(*arg,**kwds):
...     print 'Calling foo'
...     foo(*arg,**kwds)

练习使用参数:

def story(**kwds):
    return 'Once upon a time. There was a ' '%(job)s called %(name)s.' % kwds


def power(x,y,*others):
    if others:
        print 'Received redundant parameters:', others
    return pow(x,y)


def interval(start,stop=None,step=1):
    'Imitates range() for step>0'
    if stop is None:
        start,stop = 0,start
    result = []
    i = start
    while i < stop:
        result.append(i)
        i +=step
    return result


print story(job='king',name='Gumby')
print story(name='Jerry',job='king')
params = {'job':'language','name':'Python'}
print story(**params)
del params['job']
print story(job='stroke of genius',**params)
print power(2,3)
print power(3,2)
print power(y=3,x=2)
params =(5,)*2
print power(*params)
print power(2,3,'Hello,World!')
print interval(10)
print interval(1,5)
print interval(3,12,4)
print power(*interval(3,7))

D:\>python Python.py

Once upon a time. There was a king called Gumby.
Once upon a time. There was a king called Jerry.
Once upon a time. There was a language called Python.
Once upon a time. There was a stroke of genius called Python.
8
9
8
3125
Received redundant parameters: ('Hello,World!',)
8
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
[1, 2, 3, 4]
[3, 7, 11]
Received redundant parameters: (5, 6)
81

------

作用域

>>> x = 1
>>> scope = vars()
>>> scope['x']
1
>>> scope['x'] +=1
>>> x
2

>>> def foo(): x = 42
...
>>> x = 1
>>> foo()
>>> x
1
>>> def output(x): print x
...
>>> x = 1
>>> y = 2
>>> output(y)
2

>>> def combine(param): print param+external
...
>>> external = 'berry'
>>> combine('Shrub')
Shrubberry

假如局部变量跟全局变量重名该如何做呢？

>>> def comb(param):
...     print param + globals()['param']
...
>>> param='Sherry'
>>> comb('Jerry->')
Jerry->Sherry

>>> x = 1
>>> def change_global():
...     global x
...     x +=1
...
>>> x
1
>>> change_global()
>>> x
2

------

嵌套作用域: 一个函数嵌套在另一个函数里面

>>> def foo():
...     def bar():
...         print 'Hello,World!'
...     bar()
...
>>> foo()
Hello,World!

>>> def multiplier(factor):
...     def multiplyByFactor(number):
...         return number*factor
...     return multiplyByFactor
...
>>> double = multiplier(2)
>>> double(5)
10
>>> triple = multiplier(3)
>>> triple(3)
9
>>> multiplier(5)(4)
20

>>> def A(x):
        def B(y):
           def C(z):
               return x+y+z
           return C
        return B
>>> A(1)(2)(3)
6

------

------

------