分治算法求解序列最大子和问题
特别的,当序列所有整数均为负整数时,其最大子和为0。
1 #include <stdio.h> 2 3 int caluMaxSubSum(int *array, int left, int right); 4 5 int main() 6 { 7 int array[6] = {2, -2, 3, 1, -4, 2}; 8 int len_array = sizeof(array)/sizeof(array[0]); 9 int i = 0; 10 int subsum = caluMaxSubSum(array, 0, len_array); 11 for(i = 0; i < len_array; i++) 12 { 13 printf("%d ", array[i]); 14 } 15 16 printf("\n"); 17 //printf("最大子和是: "); 18 printf("subsum = %d\n", subsum); 19 return 0; 20 } 21 22 int caluMaxSubSum(int *array, int left, int right) 23 { 24 int sum = 0; 25 if(left >= right) 26 { 27 if(array[left] > 0) 28 { 29 sum = array[left]; 30 } 31 else 32 { 33 sum = 0; 34 } 35 } 36 else 37 { 38 int center = (left + right)/2; 39 int s1 = 0, s2 = 0; 40 int lefts = 0, rights = 0; 41 int i = 0; 42 int leftsum = caluMaxSubSum(array, left, center); 43 int rightsum = caluMaxSubSum(array, center + 1, right); 44 for(i = center; i >= left; i--) 45 { 46 lefts += array[i]; 47 if(lefts > s1) 48 { 49 s1 = lefts; 50 } 51 } 52 53 for(i = center + 1; i < right; i++) 54 { 55 rights += array[i]; 56 if(rights > s2) 57 { 58 s2 = rights; 59 } 60 } 61 62 sum = s1 + s2; 63 if(sum < leftsum) 64 { 65 sum = leftsum; 66 } 67 if(sum < rightsum) 68 { 69 sum = rightsum; 70 } 71 } 72 73 return sum; 74 }
关键性的思路在哪里?
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