99. Interleaving String Leetcode Python
Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2.
For example,
Given:
s1 = "aabcc"
,
s2 = "dbbca"
,
When s3 = "aadbbcbcac"
, return true.
When s3 = "aadbbbaccc"
, return false.
class Solution: # @return a boolean def isInterleave(self, s1, s2, s3): if len(s1) + len(s2) != len(s3): return False dp = [[False for j in range(len(s2) + 1)] for i in range(len(s1) + 1)] dp[0][0] = True for row in range(len(s1) + 1): dp[row][0] = s1[:row] == s3[:row] for col in range(len(s2) + 1): dp[0][col] = s2[:col] == s3[:col] for i in range(1, len(s1) + 1): for j in range(1, len(s2) + 1): dp[i][j] = (dp[i - 1][j] and s1[i - 1] == s3[j + i - 1]) or (dp[i][j - 1] and s2[j - 1] == s3[i + j - 1]) return dp[-1][-1]
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