jquery+CSS3 简易无限级纵向(上下)菜单插件
Implement int sqrt(int x)
.
Compute and return the square root of x.
分二分法和牛顿迭代法两种解法,详细请看:
http://blog.csdn.net/kenden23/article/details/14543521
二分法:
//2014-2-20 update int sqrt(int x) { double e = 0.0000001; double a = 0, b = x; double m = a + ((b-a)/2); double res = m*m - double(x); while (abs(res) > e) { if (res < 0) a = m+1; else b = m-1; m = a + ((b-a)/2); res = m*m - double(x); } return m; }
牛顿迭代法:
//2014-2-20 update int sqrt(int x) { if (x == 0) return 0; double xi1 = x, xi = 1; while (int(xi1) != int(xi)) { xi = xi1; xi1 = (double(x)/xi + xi)/2; } return xi; }
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