PHP中判断输入验证码是否一致
首先用session将随机生成的验证码的值传到页面，然后获取当前文本框中输入的值 进行对比；代码如下：
生成的随机数，把它传到session里面
<?
session_start(); 必须要先打开session开关。
$s =
array("a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z","0","1","2","3","4","5","6","7","8","9");
$r="";
for($i=1;$i<=4;$i++){
$r .=
$s[rand(0,count($s)-1)];
}
$_SESSION[‘nb‘] = $r;
?>
然后写Ajax代码如下：
function checkYZM(){
getXmlhttp();
xmlHttp.open("GET","chekYZM.php?YZM="+yzm.value,"false");
xmlHttp.onreadystatechange = function(){
if(xmlHttp.readyState
==4){
if(xmlHttp.status == 200){
var txt =
parseInt(xmlHttp.responseText);
if(txt){
tS5.innerHTML = "验证成功";
}else{
tS5.innerHTML = "验证失败";
}
}
}
}
xmlHttp.send(null);
}
最后在chekYZM.php页面里进行判断：
<?php
session_start();
if(isset($_GET[‘YZM‘])){
$yzm = $_GET[‘YZM‘];
if($yzm ==
$_SESSION[‘nb‘]){
echo"1";
}else{
echo"0";
}
}
?>
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