js php xmlrequest 上传图片
本来想用插件上传图片的，后来自己写了一个简单的js实现异步的图片上传，不多说上代码非常简单
upload.php
<?php
if(isset($_FILES["myfile"])){
$ret = array();
$uploadDir = ‘images‘.DIRECTORY_SEPARATOR.date("Ymd").DIRECTORY_SEPARATOR;
$dir = dirname(__FILE__).DIRECTORY_SEPARATOR.$uploadDir;
file_exists($dir) || (mkdir($dir,0777,true) && chmod($dir,0777));
if(!is_array($_FILES["myfile"]["name"])) //single file
{
$fileName = time().uniqid().‘.‘.pathinfo($_FILES["myfile"]["name"])[‘extension‘];
move_uploaded_file($_FILES["myfile"]["tmp_name"],$dir.$fileName);
$ret[‘file‘] = DIRECTORY_SEPARATOR.$uploadDir.$fileName;
}
echo json_encode($ret);
}
?>
index.html
<!DOCTYPE html>
<html>
<head>
<title>Html5 Ajax 上传文件</title>
<meta charset="utf-8">
<script type="text/javascript">
var xhr;
function createXMLHttpRequest()
{
if(window.ActiveXObject)
{
xhr = new ActiveXObject("Microsoft.XMLHTTP");
}
else if(window.XMLHttpRequest)
{
xhr = new XMLHttpRequest();
}
}
function UpladFile()
{
var fileObj = document.getElementById("file").files[0];
var FileController = ‘upload.php‘;
var form = new FormData();
form.append("myfile", fileObj);
createXMLHttpRequest();
xhr.onreadystatechange = handleStateChange;
xhr.open("post", FileController, true);
xhr.send(form);
}
function handleStateChange()
{
if(xhr.readyState == 4)
{
if (xhr.status == 200 || xhr.status == 0)
{
var result = xhr.responseText;
var json = eval("(" + result + ")");
alert(‘图片链接:\n‘+json.file);
}
}
}
</script>
<style>
.txt{ height:28px; border:1px solid #cdcdcd; width:670px;}
.mybtn{ background-color:#FFF; line-height:14px;vertical-align:middle;border:1px solid #CDCDCD;height:30px; width:70px;}
.file{ position:absolute; top:0; right:80px; height:24px; filter:alpha(opacity:0);opacity: 0;width:260px }
</style>
</head>
<body>
<div class="form-group">
<label class="control-label">图片</label>
<br/>
<input type=‘text‘ name=‘textfield‘ id=‘textfield‘ class=‘txt‘ />
<span onclick="file.click()" class="mybtn">浏览...</span>
<input type="file" name="file" class="file" id="file" size="28" onchange="document.getElementById(‘textfield‘).value=this.value" />
<span onclick="UpladFile()" class="mybtn">上传</span>
</div>
</body>
</html>
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