一个简单json数据提交实例

浏览数：23 / 时间：2015年06月09日

1.客户端编程：jsp页面
<%@ page language="java" contentType="text/html; charset=UTF-8"

pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
</head>
<script type="text/javascript" src="js/jquery-1.4.2.js"></script>
<script type="text/javascript" src="js/json2.js"></script>
<body>
<form action="">
<table>
<tr>
<td>名字</td>
<td><input type="text" id="name" name="name"/></td>
</tr>
<tr>
<td>年龄</td>
<td><input type="text" id="age" name="age"/></td>
</tr>
<tr>
<td><input type="button" value="提交" onclick="commit();"/> </td>
</tr>
</table>
<table id="ulist" border="2">
</table>
</form>
</body>
<script type="text/javascript">
function commit(){

$.ajax(

{type : "post",
data:{name: $ (‘#name‘).val(),

                      age: $ (‘#age‘).val()},
           url : "testJson_testJson.action",
           dataType : "JSON",
           success : callback
               }
           );

}
function callback(data){
var json = JSON.parse(data);
alert("fdf");

var ulist = $("#ulist");

$.each(json, function(i,item){

         ulist.append(
        "<tr><td>"+item.name+"</td><td>"+item.age+"</td></tr>"
                 );
       })
}
</script>
</html>
2.服务端编程：用到sturst2

public class Person {
    private String name;
    private String age;
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public String getAge() {
        return age;
    }
    public void setAge(String age) {
        this.age = age;
    }

}

public class TestJsonAction {

    private static final long serialVersionUID = -3571998877536556903L;

    public String testJson() throws Exception {
        Person p1 = new Person();
        p1.setName("nn");
        p1.setAge("11");
        Person p2 = new Person();
        p2.setName("gg");
        p2.setAge("12");
        Person p3 = new Person();
        p3.setName("rr");
        p3.setAge("24");
        List<Person> ulist = new ArrayList<Person>();
        ulist.add(p1);
        ulist.add(p2);
        ulist.add(p3);
        String name =ServletActionContext.getRequest().getParameter("name");
        String age = ServletActionContext.getRequest().getParameter("age");
        Person p4 = new Person();
        p4.setName(name);
        p4.setAge(age);
        ulist.add(p4);
        JSONArray json = JSONArray.fromObject(ulist);
        ServletActionContext.getResponse().getWriter().print(json);
        return null;
    }

}

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一个简单json数据提交实例