Oracle中排序列中值相同引发的问题（译）
This queston came up on the Oracle newsgroup a few days ago:
这个问题在Oracle的新闻中心被提出了一段时间：
I have a table (call it policy) with three columns a, b and c. The table has two rows, with column c having value zero for both rows. I run the following query
有个表（表名是Policy），有三个字段：a、b、c，这个表有两行，c列中的数据始终为0，我运行一下的sql语句
select * from policy order by c;
As both the rows have a value of zero, the result should be sorted ascending by rowid, but I see the opposite; viz. the result set is sorted descending by rowid.
照理说，结果应该按照rowid来升序排序，但是相反的是，结果却按照rowid降序排序。
Is that an issue with the version of 10g server, I am using or is it some settings of the Oracle server?
这个是10g的问题，还是我使用的问题，或者还是设置的问题？
Various people replied to say that you should never assume any ordering beyond the order you explicitly state in the order by clause. But the question does raise a couple of interesting points.
其他的人说，最好是显式的声明排序的条件，比如rowid desc。但是这个问题引发了一个有趣的观点。
Let’s start by running the test (it’s not hard to write up a test case, so why not do so when you ask the question). The following is good enough – and I’ve appended the output of the query when running on 10.2.0.1:
当你遇到问题的时候，最好写一个测试的例子，例如下面的例子，运行在10.2.0.1上：
drop table t1; create table t1 (a number, b number, c number); insert into t1 values(1,1,0); insert into t1 values(1,1,0); commit; select t1.*, t1.rowid from t1 order by c; A B C ROWID ---------- ---------- ---------- ------------------ 1 1 0 AAATncAAGAAABSKAAB 1 1 0 AAATncAAGAAABSKAAA
2 rows selected. Sure enough, the results are in the “wrong” order.
两行数据被查询出来，果然数据排序错误。
So what do you do next ? The first couple of ideas are: add a third, fourth and fifth row to see if the “descending order” observation is accurate; then try running the test on a different version of Oracle.
接下来你要怎么做？第一个想法是，添加第三行、第四行、第五行数据，查看“descending order”是否准确，然后运行在不同版本的oracle中。
Here’s the output from 10.2.0.1, after adding more and more rows:
下面的结果集是在10.2.0.1中添加第三行、第四行、第五行数据，并查询的结果
A B C ROWID ---------- ---------- ---------- ------------------ 1 1 0 AAATncAAGAAABSKAAA 1 1 0 AAATncAAGAAABSKAAC 1 1 0 AAATncAAGAAABSKAAB A B C ROWID ---------- ---------- ---------- ------------------ 1 1 0 AAATncAAGAAABSKAAA 1 1 0 AAATncAAGAAABSKAAD 1 1 0 AAATncAAGAAABSKAAC 1 1 0 AAATncAAGAAABSKAAB A B C ROWID ---------- ---------- ---------- ------------------ 1 1 0 AAATncAAGAAABSKAAA 1 1 0 AAATncAAGAAABSKAAB 1 1 0 AAATncAAGAAABSKAAE 1 1 0 AAATncAAGAAABSKAAD 1 1 0 AAATncAAGAAABSKAAC
The results are NOT in descending order of rowid – it just looks that way in the very first case.
结果是并没有按照rowid进行降序排序，
But here’s the output from the same test running on 9.2.0.8:
同样的测试运行在9.2.0.8：
A B C ROWID ---------- ---------- ---------- ------------------ 1 1 0 AAALJkAAJAAABIKAAA 1 1 0 AAALJkAAJAAABIKAAB A B C ROWID ---------- ---------- ---------- ------------------ 1 1 0 AAALJkAAJAAABIKAAA 1 1 0 AAALJkAAJAAABIKAAB 1 1 0 AAALJkAAJAAABIKAAC A B C ROWID ---------- ---------- ---------- ------------------ 1 1 0 AAALJkAAJAAABIKAAA 1 1 0 AAALJkAAJAAABIKAAB 1 1 0 AAALJkAAJAAABIKAAC 1 1 0 AAALJkAAJAAABIKAAD A B C ROWID ---------- ---------- ---------- ------------------ 1 1 0 AAALJkAAJAAABIKAAA 1 1 0 AAALJkAAJAAABIKAAB 1 1 0 AAALJkAAJAAABIKAAC 1 1 0 AAALJkAAJAAABIKAAD 1 1 0 AAALJkAAJAAABIKAAE
So is seems more likely that there is a sorting effect (possibly accidental) on rowids in 9.2.0.8.
在9.2.0.8中，是按照rowid进行了升序排序
The Answer
Oracle introduced a new sorting algorithm (sometimes known as the Version 2 sort, which is how it is labelled in the 10032 trace) in 10.2.
答案
Oracle 10.2引入了一个新的排序算法，称为版本2。
The previous algorithm was effectively building an in-memory index on the incoming data using a balanced binary tree and seeking to the righ (i.e. optimised towards data that appeared in the correct order and keeping such data in the order of appearance - hence the apparent sorting of rowids in our example in 9i).
前面的例子有效的构建一个内存中索引输入数据使用平衡二叉树和（即优化对数据出现在正确的顺序和保持这些数据出现的顺序，明显的例子就是9i的查询结果）
The CPU and memory overheads for this algorithm are a bit fierce for large sorts, so the new algorithm does something completely different (possibly based on a variant of the heapsort, though it isn’t actually a heapsort) which is more efficient on memory and CPU. It has the side-effect though, of re-ordering incoming rows even when the data is not arriving out of order.
这个算法的cpu和内存开销有点大，所以新的算法做了一些改变。类似于堆排序的一种变体，但不是堆排序。它也有副作用，就是重新排序行
Someone who knew their sorting algorithms really well might even be able to infer the algorithm Oracle was using by extending the test case and watching the rowids re-ordering themselves as the result set grows. But I’m not going to volunteer for that task.
人们知道他们的排序算法很好，但是我不愿意做小白鼠。
If you want to disable the new sorting mechanism, there is a hidden parameter to affect it. As usual, you shouldn’t use hidden parameters without first receiving confirmation from Oracle support that you need to, but the relevant parameter is: _newsort_enabled, which defaults to true in 10g.
如果你想禁用新的排序机制，有个隐藏的参数“_newsort_enabled”，默认为true。
原文出处：http://jonathanlewis.wordpress.com/2007/06/03/sorting/
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