[Oracle]在数据库中实现地图匹配
The method to do the map match
1 The algorithm procedures
First ,we should find the most nearest road to the point from all roads in haerbin;
Second, we should find the most nearest point to the point from the road.
For example, as figure 1 ,we will do the map match for the point O.
First ,we choose the most nearest road A by compare the distance between O and A with the distance between O and B.
Second, we choose the most nearest point A3 by compare the distance between O and A1,
the distance between O and A2, the distance between O and A3 with the distance between O and A4.
Figure 1
2 The algorithm code – oracle
select g.id into abcid from h_gl g where
sdo_nn(g.geom,SDO_GEOMETRY(2001,8307,SDO_POINT_TYPE(In_X,In_Y, null),NULL,NULL),‘SDO_NUM_RES=1‘)=‘TRUE‘;
Select sdo_lrs.convert_to_lrs_geom(sdo_lrs.project_pt(g.geom,m.DIMINFO, sdo_geometry(3001, 8307,
null, sdo_elem_info_array(1, 1,1), sdo_ordinate_array(In_X, In_Y, null))))
v_sql :=‘update table t set t.road_id=‘||abcid||‘,t.longtitude_newgps =‘||v_taxi_pt.SDO_ORDINATES(1) ||‘,
t.latitude_newgps=‘||v_taxi_pt.SDO_ORDINATES(2)||‘ where t.gpsdata_id =‘||IN_GPSDATA_ID;
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