Pythonchallenge一起来闯关(二)
这一篇来闯关10-15.感觉这几关比先前的难了不少,有的题目完全没思路.
页面源码中的链接点击后有a = [1, 11, 21, 1211, 111221,
google之后知道这是一个叫做http://en.wikipedia.org/wiki/Look-and-say_sequence的数列.下面是一种比较简洁的解法.
import re x="1" for each in range(5): print(x) l = re.findall(r"(\d)(\1*)", x) print(l) x="".join([str(len(i+j))+i for i,j in re.findall(r"(\d)(\1*)", x)]) #re.findall()返回一个元祖的list,元祖的元素个数为表达式中group的个数 #re中\number表示匹配group(number)匹配到的内容,比如说(\d)(\1)如果(\d)匹配的是2,那么这里的\1则要匹配数字2 #如果(\d)匹配到的是1,那么这里的\1则要匹配数字1 #print(x) print(len(x))
根据提示 “odd even"猜想取出坐标(x，y)一个为奇数一个为偶数的像素点.按这个思路写完之后发现不对,换个思路,将原图中坐标(x，y)一个为奇数一个为偶数的像素点去除(将该点像素设成黑色(0，0，0)).得到答案。
import urllib.request as ur from PIL import Image def main(): #需要用户名密码访问url url = "http://www.pythonchallenge.com/pc/return/cave.jpg" username = ‘huge‘ password = ‘file‘ p = ur.HTTPPasswordMgrWithDefaultRealm() p.add_password(None, url, username, password) handler = ur.HTTPBasicAuthHandler(p) opener = ur.build_opener(handler) ur.install_opener(opener) dataBytes = ur.urlopen(url).read() f = open("11_cave.jpg","wb") f.write(dataBytes) im = Image.open("11_cave.jpg") w,h = im.size mode = im.mode bands = im.getbands() print(w,h) print(type(mode),mode) print(type(bands),bands) #imAnswer = Image.new(mode,(w,h),(255,255,255)) for i in range(w): for j in range(h): if (i + j)%2 == 1: pos = (i,j) im.putpixel(pos,0) im.save(‘11answer.jpg‘) if __name__ == ‘__main__‘: main()
完全没有思路的一道题.搜索之后知道是有5张图片,二进制的数据被写到了一个叫做evil2.gfx的文件中,需要像挨个发牌一样一字节一字节的重新"发回到"5个图片文件....
太考验发散思维了...
import urllib.request as ur def main(): #需要用户名密码访问url url = "http://www.pythonchallenge.com/pc/return/evil2.gfx" username = ‘huge‘ password = ‘file‘ p = ur.HTTPPasswordMgrWithDefaultRealm() p.add_password(None, url, username, password) handler = ur.HTTPBasicAuthHandler(p) opener = ur.build_opener(handler) ur.install_opener(opener) dataBytes = ur.urlopen(url).read() f = open("12_evil2.gfx","wb") f.write(dataBytes) print(len(dataBytes)) types = [‘jpg‘,‘png‘,‘gif‘,‘png‘,‘jpg‘] for i in range(5): imagedata = dataBytes[i::5] image = open(‘12answer_%d.%s‘ % (i,types[i]),‘wb‘) image.write(imagedata) if __name__ == ‘__main__‘: main()
执行代码后,有5张图片,前面4张字母连起来就是答案.用二进制的方式打开图片文件.可以看到.jpg文件的首字节0xff,.png文件的首字节为0x89,猜测应该是首字节或者是前几字节
代表图片的格式的字段,没有去深究.
页面源码中有一个链接指向phonebook.php,点击进入以后出现提示:This XML file does not appear to have any style information associated with it. The document tree is shown below.google之后知道是少了某些描述文件,可以简单理解为类似于html中缺少了css,所以浏览器就无法正常展示格式吧.然而还是不知道要如何继续下去,去标准库中查找xml相关的内容,还是没啥思路.继续google页面中的节点名称<methodResponse>,找到了xmlrpc---xml远程调用,到这里问题就简单了.代码如下:
import xmlrpc.client def main(): x = xmlrpc.client.ServerProxy("http://www.pythonchallenge.com/pc/phonebook.php") print(x.system.listMethods()) print(x.phone(‘Bert‘)) if __name__ == ‘__main__‘: main()
XML-RPC is a Remote Procedure Call method that uses XML passed via HTTP as a transport. With it, a client can call methods with parameters on a remote server (the server is named by a URI) and get back structured data.类似于webservice,server端实现了一些功能,并提供一些接口给客户端使用.
import urllib.request as ur from PIL import Image l = [[i, i-1, i-1, i-2] for i in range(100, 0, -2)] #print(l) def main(): im = Image.open("wire.png") #print(im.size) (width,height) = im.size mode = im.mode #pos = [(x,y) in range(width,height)] #print(pos) #print(width,height) #print(im.getpixel((639,486))) x,y=0,0 imAnswer = Image.new(mode,(100,100),(255,255,255)) #print(imAnswer.size) #左上角为坐标(0,0),左下角为坐标(0,99),右上角坐标为(99,0),右下角坐标为(99,99) #im.getpixel((i,0)) #imAnswer.putpixel((0,0),(255,0,0)) #imAnswer.putpixel((99,0),(0,255,0)) #imAnswer.putpixel((0,99),(0,0,255)) #imAnswer.putpixel((99,99),(255,255,255)) #imAnswer.save(‘14Answer.jpg‘) lastPos=(-1,0) #上一个坐标位置 maxStep=100 #当前最多走到多少步需要变向 currentSteps=0 #当前方向已经走了多少步 currentDirection=1 #1:向右,2:向下,3:向左,4向上 for i in range(0,10000): pixel = im.getpixel((i,0)) if currentDirection == 1: pos = (lastPos[0] + 1,lastPos[1]) if currentDirection == 2: pos = (lastPos[0],lastPos[1] + 1) print(lastPos,pos) if currentDirection == 3: pos = (lastPos[0] - 1,lastPos[1]) if currentDirection == 4: pos = (lastPos[0],lastPos[1] - 1) #print(currentDirection,lastPos,pos) try: imAnswer.putpixel(pos,pixel) except: pass #print(pos) #更新点的位置信息 lastPos = pos currentSteps += 1 #处理到达边界的情况 if (currentSteps == maxStep): if currentDirection == 1: currentDirection = 2 currentSteps = 0 maxStep -= 1 #print("turn to down!",currentDirection) elif currentDirection == 2: currentDirection = 3 currentSteps = 0 elif currentDirection == 3: currentDirection = 4 currentSteps = 0 maxStep -= 1 elif currentDirection == 4: currentDirection = 1 currentSteps = 0 imAnswer.save(‘14Answer.jpg‘) if __name__ == ‘__main__‘: main()
执行完后得到一张猫的图片,输入http://www.pythonchallenge.com/pc/return/cat.html得到提示:and its name is uzi. you‘ll hear from him later.把cat换成uzi即是下一关地址.
import calendar from datetime import date yearlist = [] for x in range(0,10): for y in range(0,10): year = 1000 + x*100 + y*10 + 6 if calendar.isleap(year): yearlist.append(year) #print(yearlist) for year in yearlist: d = date(year,1,1) if d.weekday() == 3: #周一到周日:0-6 print(year) #第二年轻的,是1756年.google 1756年1月26日 第二天是莫扎特诞生
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