[leetcode]Search a 2D Matrix @ Python
浏览数：404 /
时间：2015年06月08日
原题地址：https://oj.leetcode.com/problems/search-a-2d-matrix/
题意：
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
- Integers in each row are sorted from left to right.
- The first integer of each row is greater than the last integer of the previous row.
For example,
Consider the following matrix:
[ [1, 3, 5, 7], [10, 11, 16, 20], [23, 30, 34, 50] ]
Given target = 3,
return true.
解题思路：类似于二分查找。
代码：
class Solution: # @param matrix, a list of lists of integers # @param target, an integer # @return a boolean def searchMatrix(self, matrix, target): i = 0; j = len(matrix[0]) - 1 while i < len(matrix) and j >= 0: if matrix[i][j] == target: return True elif matrix[i][j] > target: j -= 1 else: i += 1 return False
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