hdu 1548 A strange lift Dijkstra+SPFA算法AC
A strange lift
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13777 Accepted Submission(s): 5254
Here comes the problem: when you are on floor A,and you want to go to floor B,how many times at least he has to press the button "UP" or "DOWN"?
The first line contains three integers N ,A,B( 1 <= N,A,B <= 200) which describe above,The second line consist N integers k1,k2,....kn.
A single 0 indicate the end of the input.
5 1 5 3 3 1 2 5 0
3
#include <cstdio> #include <deque> #define MAX 210 #define INF 1000000000 using namespace std ; int graph[MAX][MAX] ; int t[MAX] ; bool visited[MAX] ; int SPFA(int s , int d , int n) { int dis[MAX] , c[MAX]; for(int i = 1 ; i <= n ; ++i) { dis[i] = INF ; c[i] = 0 ; visited[i] = false ; } dis[s] = 0 ; deque<int> que ; que.push_front(s) ; while(!que.empty()) { int k = que.front() ; que.pop_front() ; visited[k] = false ; c[k]++ ; if(c[k]>n) { return -1 ; } for(int i = 1 ; i <= n ; ++i) { if(dis[i]>dis[k]+graph[k][i]) { dis[i] = dis[k]+graph[k][i] ; visited[i] = true ; if(!que.empty()) { if(que.front()<=dis[i]) que.push_back(i) ; else que.push_front(i) ; } else { que.push_front(i) ; } } } } return dis[d] ; } int main() { int n , a , b ; while(~scanf("%d",&n) && n) { scanf("%d%d",&a,&b) ; for(int i = 1 ; i <= n ; ++i) { scanf("%d",&t[i]) ; } for(int i = 0 ; i <= n ; ++i) { for(int j = 0 ; j <= n ; ++j) { graph[i][j] = INF ; } } for(int i = 1 ; i <= n ; ++i) { if(i+t[i]<=n) { graph[i][i+t[i]] = 1 ; } if(i-t[i]>0) { graph[i][i-t[i]] = 1 ; } } if(b<1|b>n) { puts("-1") ; continue ; } int ans = SPFA(a,b,n) ; if(ans >= INF) puts("-1") ; else printf("%d\n",ans) ; } return 0 ; }
Dijkstra代码:
#include <stdio.h> #define MAX 210 #define INF 1000000000 int graph[MAX][MAX] ; int t[MAX] , dis[MAX]; bool visited[MAX] ; void dijkstra(int s , int n) { for(int i = 1 ; i <= n ; ++i) { dis[i] = graph[s][i] ; visited[i] = false ; } dis[s] = 0 ; //忘了写这行代码。。让我wrong成SB了 visited[s] = true ; for(int i = 1 ; i < n ; ++i) { int index = -1 , min = INF; for(int j = 1 ; j <= n ; ++j) { if(!visited[j] && dis[j]<min) { index = j ; min = dis[j] ; } } if(index == -1) { return ; } visited[index] = true ; for(int j = 1 ; j <= n ; ++j) { if(!visited[j] && dis[j]>dis[index]+graph[index][j]) { dis[j] = dis[index]+graph[index][j] ; } } } } int main() { int n , a , b ; while(~scanf("%d",&n) && n) { scanf("%d%d",&a,&b) ; for(int i = 1 ; i <= n ; ++i) { scanf("%d",&t[i]) ; } for(int i = 0 ; i <= n ; ++i) { for(int j = 0 ; j <= n ; ++j) { graph[i][j] = INF ; } } for(int i = 1 ; i <= n ; ++i) { if(i+t[i]<=n) { graph[i][i+t[i]] = 1 ; } if(i-t[i]>0) { graph[i][i-t[i]] = 1 ; } } if(b<1|b>n) { puts("-1") ; continue ; } dijkstra(a,n) ; if(dis[b] >= INF) puts("-1") ; else printf("%d\n",dis[b]) ; } return 0 ; }
与君共勉
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