HDU - 1061 Rightmost Digit
浏览数：22 /
时间：2015年06月09日
Description
Given a positive integer N, you should output the most right digit of N^N.
Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single positive integer N(1<=N<=1,000,000,000).
Each test case contains a single positive integer N(1<=N<=1,000,000,000).
Output
For each test case, you should output the rightmost digit of N^N.
Sample Input
2 3 4
Sample Output
7 6
题意：取N^N的最后一位
思路：裸的快速幂取模
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
typedef long long ll;
using namespace std;
int pow_mod(int a, int n, int m) {
if (n == 0)
return 1;
if (n == 1)
return a%m;
int x = pow_mod(a, n/2, m);
ll ans = (ll) x*x%m;
if (n % 2 == 1)
ans = ans * a % m;
return (int)ans;
}
int main() {
int t;
int n;
scanf("%d", &t);
while (t--) {
scanf("%d", &n);
ll ans = pow_mod(n, n, 10);
cout << ans << endl;
}
return 0;
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