在SQL中把一个浮点数的整数部分和小数部分分开
select item_no, actual_hours,
(actual_hours/8) as days,
--charindex(‘.‘,cast((actual_hours/8) as varchar))-1 as dianindex,
--cast(left(cast((actual_hours/8) as varchar) , charindex(‘.‘,cast((actual_hours/8) as varchar)) - 1) as int)as zhengshu,
--convert(decimal(18,4),(‘0.‘+reverse(cast(cast(reverse(substring(cast((actual_hours/8) as varchar) , charindex(‘.‘,cast((actual_hours/8) as varchar)) + 1 , len(cast((actual_hours/8) as varchar)))) as int) as varchar))))*8 as hours ,
--cast(left(cast((actual_hours/8) as varchar) , charindex(‘.‘,cast((actual_hours/8) as varchar)) - 1) as int) as days,
start_date,actual_begin_date
--into #ta
from work_item
where actual_complete_date is not null and actual_hours=8 --and charindex(‘.‘,cast((actual_hours/8) as varchar))-1<=-1
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