sql树型查询
WITH a AS ( SELECT *, FOrderPath=CAST(RIGHT(1000+FOrder,3) AS NVARCHAR(200)), FPath=CAST(Id AS NVARCHAR(200)), FLevel=0 FROM Base_Class AS a WHERE NOT EXISTS(SELECT 1 FROM Base_Class WHERE ID=a.PID) UNION ALL SELECT b.*, CAST(a.FOrderPath + RIGHT(1000+b.FOrder,3)AS NVARCHAR(200)), CAST((a.FPath + ‘,‘ + CAST(b.Id AS NVARCHAR(10)))AS NVARCHAR(200)), FLevel=FLevel+1 FROM a INNER JOIN Base_Class AS b ON b.PID=a.ID ) SELECT * FROM a ORDER BY FOrderPath
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